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mysqli::real_escape_string

PHP function Edit on GitHub ✎

(PHP 5, PHP 7, PHP 8)

Escapes special characters in a string for use in an SQL statement, taking into account the current charset of the connection

Description

Oop

mysqli::real_escape_string(string $string): string

Procedural

mysqli_real_escape_string(mysqli $mysql, string $string): string

This function is used to create a legal SQL string that you can use in an SQL statement. The given string is encoded to produce an escaped SQL string, taking into account the current character set of the connection.

Caution

The character set must be set either at the server level, or with the API function mysqli_set_charset() for it to affect mysqli_real_escape_string(). See the concepts section on character sets for more information.

Parameters

string

The string to be escaped.

Characters encoded are NUL (ASCII 0), \n, \r, \, ', ", and CTRLZ.

Return Values

Returns an escaped string.

Examples

mysqli::real_escape_string example

Oop

php
<?php

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

$city = "'s-Hertogenbosch";

/* this query with escaped $city will work */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'",
	$mysqli->real_escape_string($city));
$result = $mysqli->query($query);
printf("Select returned %d rows.\n", $result->num_rows);

/* this query will fail, because we didn't escape $city */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'", $city);
$result = $mysqli->query($query);

Procedural

php
<?php

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = mysqli_connect("localhost", "my_user", "my_password", "world");

$city = "'s-Hertogenbosch";

/* this query with escaped $city will work */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'",
	mysqli_real_escape_string($mysqli, $city));
$result = mysqli_query($mysqli, $query);
printf("Select returned %d rows.\n", mysqli_num_rows($result));

/* this query will fail, because we didn't escape $city */
$query = sprintf("SELECT CountryCode FROM City WHERE name='%s'", $city);
$result = mysqli_query($mysqli, $query);

Similar

output
Select returned 1 rows.

Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 's-Hertogenbosch'' at line 1 in...

See Also

Source: reference/mysqli/mysqli/real-escape-string.xml · from the official PHP manual (php/doc-en)