mysqli_stmt::$insert_id
Returns the value generated for an AUTO_INCREMENT column by the last statement executed
Description
Oop
int|stringmysqli_stmt->insert_id
Procedural
Returns the ID generated by an INSERT or UPDATE statement on a table with a column having the AUTO_INCREMENT attribute. In the case of a multiple-row INSERT statement, it returns the first automatically generated value that was successfully inserted. If LAST_INSERT_ID(expr) is used to set the AUTO_INCREMENT value, or in an UPDATE, the value of expr is returned instead.
Returns 0 if the statement did not change an AUTO_INCREMENT value.
Parameters
Return Values
The value of the AUTO_INCREMENT field that was updated by the statement. Returns zero if the statement has not been executed yet or if it did not update an AUTO_INCREMENT value.
The value is specific to the statement object. It is not affected by other statements executed on the same connection after this statement, nor by statements issued using other connections or clients.
If the number is greater than the maximum int value, it will be returned as a string.
Examples
mysqli_stmt::$insert_id example
Oop
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$mysqli->query("CREATE TEMPORARY TABLE myCity LIKE City");
$stmt = $mysqli->prepare("INSERT INTO myCity (Name, CountryCode, District, Population) VALUES (?, ?, ?, ?)");
$name = 'Stuttgart';
$countryCode = 'DEU';
$district = 'Stuttgart';
$population = 617000;
$stmt->bind_param('sssi', $name, $countryCode, $district, $population);
$stmt->execute();
printf("New record has ID %d.\n", $stmt->insert_id);Procedural
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
mysqli_query($link, "CREATE TEMPORARY TABLE myCity LIKE City");
$stmt = mysqli_prepare($link, "INSERT INTO myCity (Name, CountryCode, District, Population) VALUES (?, ?, ?, ?)");
$name = 'Stuttgart';
$countryCode = 'DEU';
$district = 'Stuttgart';
$population = 617000;
mysqli_stmt_bind_param($stmt, 'sssi', $name, $countryCode, $district, $population);
mysqli_stmt_execute($stmt);
printf("New record has ID %d.\n", mysqli_stmt_insert_id($stmt));Outputs
New record has ID 1.