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imagecopy

PHP function Edit on GitHub ✎

(PHP 4, PHP 5, PHP 7, PHP 8)

Copy part of an image

Description

imagecopy(GdImage $dst_image, GdImage $src_image, int $dst_x, int $dst_y, int $src_x, int $src_y, int $src_width, int $src_height): true

Copy a part of src_image onto dst_image starting at the x,y coordinates src_x, src_y with a width of src_width and a height of src_height. The portion defined will be copied onto the x,y coordinates, dst_x and dst_y.

Parameters

dst_image: Destination
src_image: Source
dst_x: x-coordinate of destination point.
dst_y: y-coordinate of destination point.
src_x: x-coordinate of source point.
src_y: y-coordinate of source point.
src_width: Width
src_height: Height

Return Values

Always

Changelog

Version	Description
8.0.0	`dst_image` and `src_image` expect `GdImage` instances now; previously, `resource`s were expected.

Examples

Cropping the PHP.net logo

php

<?php
// Create image instances
$src = imagecreatefromgif('php.gif');
$dest = imagecreatetruecolor(80, 40);

// Copy
imagecopy($dest, $src, 0, 0, 20, 13, 80, 40);

// Output and free from memory
header('Content-Type: image/gif');
imagegif($dest);
?>

The above example will output something similar to: Output of example : Cropping the PHP.net logo